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(C) The damping force $F$ is directly proportional to the velocity $v$,which can be written as $F = kv$,where $k$ is the constant of proportionality.F

Vedclass · Accepted Answer

$Kg\ s^{-1}$

Vedclass · Answer

(C) The damping force $F$ is directly proportional to the velocity $v$,which can be written as $F = kv$,where $k$ is the constant of proportionality.From this equation,we can express $k$ as $k = \frac{F}{v}$.The $SI$ unit of force $F$ is Newton $(N)$,which is equivalent to $kg\ m\ s^{-2}$.The $SI$ unit of velocity $v$ is $m\ s^{-1}$.Substituting these units into the expression for $k$:$k = \frac{kg\ m\ s^{-2}}{m\ s^{-1}} = kg\ s^{-1}$.Therefore,the unit of the constant of proportionality is $kg\ s^{-1}$.

List-$I$	List-$II$
$A$. Coefficient of viscosity	$I$. $[ML^{-1}T^{-2}]$
$B$. Surface tension	$II$. $[ML^2T^{-2}]$
$C$. Pressure	$III$. $[ML^0T^{-2}]$
$D$. Surface energy	$IV$. $[ML^{-1}T^{-1}]$

The damping force on an oscillator is directly proportional to the velocity. The units of the constant of proportionality are:

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Two quantities $A$ and $B$ are related by the equation $A/B = m$,where $m$ is linear density and $A$ is force. The dimensions of $B$ are equivalent to which of the following?

Match List-$I$ with List-$II$.
List-$I$ List-$II$
$A$. Coefficient of viscosity $I$. $[ML^{-1}T^{-2}]$
$B$. Surface tension $II$. $[ML^2T^{-2}]$
$C$. Pressure $III$. $[ML^0T^{-2}]$
$D$. Surface energy $IV$. $[ML^{-1}T^{-1}]$

Choose the correct answer from the options given below:

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